Enthalpy of neutralization of CH3COOH and NaOH is 55.9 kJ. What is the value of ΔH for ionization of CH3COOH?
The heat of neutralization of strong acid and strong base + ΔH of ionization of CH3COOH = Enthalpy of neutralization of CH3COOH and NaOH ∴ – 57.1 kJ + ΔH of ionisation of CH3COOH = – 55.9 kJ ∴ ΔH of ionisation of CH3COOH = (- 55.9 + 57.1) kJ = 1.2 kJ.
