What would be the heat released when 0.35 mol of HC1 in solution is neutralized by 0.25 mol of NaOH solution?
HCl and NaOH being strong acid and strong- base is completely ionization in dilute aqueous solutions. The net reaction is H + (0.25 mol) + OH– (0.25. mol) → H2O (0.25 mol) Now the heat of neutralization of 1 mole of a strong acid is – 57.1 kJ ∴ The heat released will be 57.1 × 0.25 kJ = 14.27 kJ.
