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Ananya Shree

Class 11th
Chemistry
2 years ago

The ionization constants of HF = 6.8 × 10-4. Calculate the ionization constant of the corresponding conjugate base.

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Muskan Anand

2 years ago

Kb = Kw Kc=10−146.8×10−4 = 1.47 × 10-11.

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