On the basis of quantum numbers, justify that the sixth period of the periodic table should have 32 elements.
In the periodic desk of the elements, a duration shows the price of the most important quantum number (n) for the outermost shells. Each length starts with the filling of primary quantum number (n). The fee of n for the 6th duration is 6. For n = 6, azimuthal quantum number (l) may have values of 0, 1, 2, 3, 4. According to Aufbau's principle, electrons are introduced to unique orbitals so as in their growing energies. The electricity of the 6d subshell is even better than that of the 7s subshell. In the 6 th duration, electrons may be stuffed in handiest 6s, 4f, 5d, and six p subshells. Now, 6s has one orbital, 4f has seven orbitals, 5d has 5 orbitals, and 6p has 3 orbitals. Therefore, there are a complete of sixteen (1 7 5 3 = sixteen) orbitals available. According to Pauli's exclusion principle, every orbital can accommodate a most of two electrons. Thus, sixteen orbitals can accommodate a most of 32 electrons. Hence, the 6th duration of the periodic desk need to have 32 elements.
