Find the number of voids in 0.2 moles of a compound forming hexagonal close-packed structure. What number of these are tetrahedral voids?
Number of atoms in close packaging = 0.5 mol 1 has 6.022×1023 particles So that Number of close-packed particles =0.5×6.022×1023=3.011×1023 Number of tetrahedral voids = 2 × number of atoms in close packaging Plug the values we get Number of tetrahedral voids =2×3.011×1023 =6.022×1023 Number of octahedral voids = number of atoms in close packaging So that Number of octahedral voids =3.011×1023 Total number of voids = Tetrahedral void + octahedral void =6.022×1023+3.011×1023 =9.03×1023
