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Ananya Shree

Class 12th
Physics
2 years ago

Check that the ratio ke2/G memp is dimensionless. Look up a Table of Physical Constants and determine the value of this ratio. What does the ratio signify?

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Muskan Anand

2 years ago

The given ratio is Gmc​mp​ke2​ Where, G= Gravitational constant Its unit is Nm2kg−2. me​ and mp​= Masses of electron and proton. Their unit is kg. e= Electric charge. Its unit is C. k=A constant    =4π∈0​1​ ∈0​= Permittivity of free space Its unit is Nm2C−2.  Unit of the given ratio Gmc​mp​ke2​=[Nm2kg−2][kg][kg][Nm2C2][C−2]​                                                                         =M0L0T0 Hence, the given ratio is dimensionless. e=1.6×10−19C G=6.67×10−11Nm2kg−2 2 me​=9.1×106−31kg mp​=1.66×10−27kg Gmc​mp​ke2​=6.67×10−11×9.1×10−3×1.67×10−229×109×(1.6×10−19)2​≈2.3×1039 This is the ratio of electric force to the gravitational force between a proton and an electron, keeping distance between them constant.

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