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Ananya Shree

Class 12th
Physics
2 years ago

If Coulomb’s law involved 1/r3 dependence (instead of 1/r2), would Gauss’s law be still true?

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Muskan Anand

2 years ago

In this case the the electric field due to point charge q is E=r2kq​ Now consider a gaussian surface as a sphere surface of radius r The flux through the surface is ϕ=∮E.dS=(kq/r3)∮dS=kq/r3×4πr2=r4πkq​ Thus this flux is dependent on r but from Gauss's law the flux depends only on the charge inside the surface. 

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