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Ananya Shree

Class 12th
Physics
2 years ago

Calculate potential on the axis of a ring due to charge Q uniformly distributed along the ring of radius R.

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Muskan Anand

2 years ago

Let us consider a ring of radius R having charge +Q distributed uniformly. Also a point P at distance z on its axis passing through centre 0 and perpendicular to plane of ring. Again consider an element of ring at S of length di having charge dq and SP is equal to r. Then potential energy due to element to r. Then potential energy due to element dl at P, dV=r−kdq​ where k=4πε0​1​ Charge on 2πR length of ring =Q Charge on dl length of ring =2πRQ​dl So potential due to element di at P dV==2πR−k⋅Q⋅dl​ Integrating over a ring the potential at P,VP​ 0∫v​dVp​=0∫2πR​2πRrkQdl​ where r=R2+z2​ Vp​=2πRR2+z2​kQ2πR​=4πε0​R2+z2​Q​ Charge on 2Charge on 2\piR length of ring = Charge on dl length of ring =2πRQ​dl So potential due to element di at P dV==2πR−k⋅Q⋅dl​ Integrating over a ring the potential at P,VP​ ∫0v​dVp​=∫02mR​2πRrkQa1​ where r=R2+z2​ Vp​=2πRR2+z2​kQ2πR​=4πε0​R2+z2​Q​

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Muskan Anand

2 years ago

Let us consider a ring of radius R having charge +Q distributed uniformly. Also a point P at distance z on its axis passing through centre 0 and perpendicular to plane of ring. Again consider an element of ring at S of length di having charge dq and SP is equal to r. Then potential energy due to element to r. Then potential energy due to element dl at P, dV=r−kdq​ where k=4πε0​1​ Charge on 2πR length of ring =Q

user image

Ananya Shree

2 years ago

Let us consider a ring of radius R having charge +Q distributed uniformly. Also a point P at distance z on its axis passing through centre 0 and perpendicular to plane of ring. Again consider an element of ring at S of length di having charge dq and SP is equal to r. Then potential energy due to element to r. Then potential energy due to element dl at P, dV=r−kdq​ where k=1/4πε0

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