At room temperature (27.0 °C) the resistance of a heating element is 100 Ω. What is the temperature of the element if the resistance is found to be 117 Ω, given that the temperature coefficient of the material of the resistor is 1.70 × 10–4 °C–1.
Step 1: Relation between value of resistance and temperature R=R0[1+α(T−T0)] Step 1: Temperature calculation Let T is the increased temperature of the element, putting all the values in the formula to find T T0=27oC, R0=100Ω, R=117Ω, α=1.70×10−4 oC−1 ⇒117=100[1+1.7×10−4(T−27)] ⇒T=1027oC
