If the solenoid in Exercise 5.5 is free to turn about the vertical direction and a uniform horizontal magnetic field of 0.25 T is applied, what is the magnitude of the torque on the solenoid when its axis makes an angle of 30° with the direction of applied field?
Here, τ=MBsinθ M=0.6Am2B=0.25T θ=30o ∴τ=0.6×0.25×sin30o=0.075Nm
