A 60 µF capacitor is connected to a 110 V, 60 Hz ac supply. Determine the rms value of the current in the circuit.
Given: The capacitance of the capacitor is 60μF. The RMS value of the voltage supplied is 110V. The frequency of the AC supply is 60Hz. To find: The RMS value of the current. We know that the impedance of the capacitor is determined by: XC=ωC1=2πfC1⇒2×3.14×60×60×10−61 ⇒44.2Ω The RMS value of the current is obtained as Irms=XCE ⇒44.2110⟹2.49 A
