Use the mirror equation to deduce that: an object placed between the pole and focus of a concave mirror produces a virtual and enlarged image.
For a concave mirror, the focal length (f) is negative. When the object is placed on the left side of the mirror, the object distance (u) is negative For image distance v we can write v1+u1=f1 v1=f1−u1 ...(1) The object lies between f and 2f. 2f<u<f 2f1>u1>f1 2f−1<u−1<f−1 f1−2f1<f1−u1 .......(2) from eq. 1 2f1<v1<0 ; v is negative 2f>v −v>−2f Therefore, the image lies beyond 2f
