Two particles A1 and A2 of masses m1, m2 (m1 > m2) have the same de Broglie wavelength. Then (a) their momenta are the same (b) their energies are the same (c) energy of A1 is less than the energy of A2 (d) energy of A1 is more than the energy of A2
Correct option is A) As λ=phorp=λhorp∝λ1 ∴p2p1=λ1λ2=λλ=1orp1=p2 ..............(1) Also E=21mp2=2m1λ2h2(∴p=λh) or E∝m1∴E2E1=m1m2<1orE1<E2 ................(2)
