The de Broglie wavelength of a photon is twice the de Broglie wavelength of an electron. The speed of the electron is ve = c/100. Then (a) Ee/Ep = 10-4 (b) Ee/Ep = 10-2 (c) Pe/mec = 10-2 (d) Pe/mec = 10-4
Correct option is B) λe=meveh =me(c/100)h =mec100 K.E, Ee=21meve2 meve=2Eeme λ=mev2h =2meEeh Ee=2λ2meh2 EeEp=2λehc×h22λ2me=hλemec =mec100h×hmec=100 EeEp=1001=10−2 For electron Pe=mev2=me×100c=10−2
