Assuming an electron is confined to a 1nm wide region, find the uncertainty in momentum using the Heisenberg Uncertainty principle. You can assume the uncertainty in position ∆x as 1nm. Assuming p = ∆p, find the energy of the electron in electron volts.
Here Δx=1nm=10−9m By Heisenberg uncertainty principle, ΔxΔp=h ∴ Δp=Δxh=2πΔxh [∵h=2πh] =2×π×10−96.63×10−34=1.05×10−25kgms−1
