A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
Given: The difference in energy between the two energy levels is 2.3eV. To find: The frequency of radiation emitted when the atom makes a transition between the energy levels. The energy between the energy levels is E=2.3eV⇒2.3×1.6×10−19J The frequency of the radiations emitted during transition is: E=hν ν=Eh ⇒2.3×1.6×10−196.626×10−34 ⇒5.5×1014Hz
