Would the Bohr formula for the H-atom remain unchanged if proton had a charge (+4/3)e and electron a charge (−3/4)e, where e = 1.6 × 10–19C? Give reasons for your answer.
According to Bohr, for an electron around a stationary nucleus the electrostatics force of attraction provides the necessary centripetal force. 4πϵ01r2q1q2=rmv2 Hence the magnitude of electrostatic force F ∞ q1 x q2If proton had a charge (+4/3)e and electron a charge (-3/4)e, then the Bohr formula for the H-atom remains same, since the Bohr formula involves only the product of the charges which remain constant for given values of charges
