Assuming the ideal diode. Explain the waveform.
When signal 20sinωt gives input voltage less than 5 volt (because after 5V diode will get positive voltage at its P-junction) then diode will be in reverse bias so resistance of diode remain infinity so input signal will not pass through diode and battery path so output across A and B will increase from 0−5V (graph OC). Now when the input voltage 20sinωt increase beyond 5V then path of diode 5V battery will offer very low resistance, so the current passes through diode and battery and output (across A and B) remain 5V (graph CD). Now when the voltage decreases the diode will be in reverse bias and output will again fall from 5V to 0V as input changes (graph ED). When input voltage become negative (there is opposite of 5V battery in p-n junction input voltage becomes more than 5V now) the diode is in reversed bias it will not conduct current through CD, and in output across AB will get same as input AC ie., for negaive cycle diode offer infinite resistance as compared to R in series graph E,F,G Same repetition of input and output continues-graph showing the output waveform .
