Calculate emf of the following cell at 298K.
Cell reaction is as follows. Zn(s)+ Cu2+(aq)→ Zn2+(aq) + Cu(s) Zn(s)+ Cu2+(aq)→ Zn2+(aq) + Cu(s) n = 2 and T = 298 K Ecell=(E0Cu2+/Cu−E0Zn2+/Zn)−0.0591nlog [Zn2+(aq)][Cu+2(aq)]Ecell=(ECu2+/Cu0−EZn2+/Zn0)−0.0591nlog [Zn2+(aq)][Cu+2(aq)] Ecell=0.34V−(−0.76)−0.05912log10−410−2Ecell=0.34V−(−0.76)−0.05912log10−410−2 Ecell=1.10−0.02955log10−2Ecell=1.10−0.02955log10−2 =1.10+2×0.02955=1.10+2×0.02955 ∴Ecell=+1.1591V∴Ecell=+1.1591V
