The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate EaEa .
Given T1=298KT1=298K T2=(298+10)KT2=(298+10)K We also know that when the temperature is raised by 10 degrees Celsius, the reaction rate doubles. As a result, we'll use the values k1 = kk1 = k and k2 = 2kk2 = 2k . R=8.314JK−1mol−1R=8.314JK−1mol−1 On substitution k2k1=Ea2.303R[T2−T1T1T2]k2k1=Ea2.303R[T2−T1T1T2] log2kk=Ea2.303×8.314[10298×308]log2kk=Ea2.303×8.314[10298×308] Ea=2.303×8.314×298×308×log210Ea=2.303×8.314×298×308×log210 =52897.78 J mol - 1=52897.78 J mol - 1 =52.89 kJ mol - 1
