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Preeti Tripathi

Class 9th
Maths
2 years ago

Expand : (i) (y – √3)2 (ii) (x – 2y – 3z)2

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Abhishek Mishra

2 years ago

Solution: (i) (y – √3)2 = y2 -2 × y × √3 + (√3)2 = y2 – 2√3 y + 3 (x – 2y – 3z)2 = x2 + 1 – 2y)2 + (-3z)2 + 2 × x × (-2y) + 2 × (-2y) × (-3z) + 2 × (-3z) × x = x2 + 4y2 + 9z2 – 4xy + 12yz – 6zx

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