What are the possible expressions for the dimensions of a cuboid whose volume is given below ? Volume = 12ky2 + 8ky – 20k.
Solution: We have, volume = 12ky2 + 8ky – 20k = 4k(3y2 + 2y – 5) = 4k(3y2 + 5y – 3y – 5) = 4k[y(3y + 5) – 1(3y + 5)] = 4k(3y + 5) (y – 1) ∴Possible expressions for the dimensions of cuboid are 4k units, (3y + 5) units and (y – 1) units.
