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Preeti Tripathi

Class 9th
Maths
2 years ago

If x = 2 – √3, y = √3 – √7 and 2 = √7 – √4, find the value of x’ + 43 + 2?.

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Abhishek Mishra

2 years ago

Solution: Here, x + y + z = 2 – √3+ √3 – √7+√7 – 2 = 0 x3+ √3 + x3= 3(x)(y)(z) = 3(2 – √3)(√3 – √7)(√7 – 2) = 3(2√3 – 2√7 – 3 + √21)(√7 – 2) = 3(2√21 – 14 – 3√7 + 7√3 – 4√3 + 4√7 + 6 – 2√21) = 3(3√3 + √7 – 8)

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