In Fig. , ABC is a right triangle right angled at A. BCED, ACFG and ABMN are squares on the sides BC, CA and AB respectively. Line segment AX ⊥ DE meets BC at Y. Show that: (vii) ar (BCED) = ar (ABMN) + ar (ACFG)

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Abhishek Mishra

1 year ago

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