The brakes applied to a car produce an acceleration of 6 m/s2 in the opposite direction to the motion. If the car takes 2 s to stop after the application of brakes, calculate the distance it travels during this time
Step 1, Given data Acceleration a=−6 m/s2 Time t=2 s Final velocity v=0 m/s Let initial velocity be u Step 2, Finding the distance From the third equation of motion, v2−u2=2as Putting values 02−u2=2(−6)s 12s=u2-----------------------(1) Let distance be s From the first equation. of the motion we get' v=u+at So, 0=u+(−6)(2) So, u=12m/s put the value of u in equation (1) We get 12×s=122⟹s=12m Hence the distance traveled is 12 m
