Draw velocity time graph for a body that has initial velocity ‘u’ and is moving with uniform acceleration ‘a’. Use it to derive v = u + at; s = ut + 1 2 at2 , and v2 = u 2 + 2as
Let ′u′ be the initial velocity ′v′ be the velocity at time ′t′ and ′a′ be the acceleration. The distance travelled by the body in ′t′ second = area enclosed between the velocity-time graph and x−axis Or Distance traveled by the body in ′t′ seconds = area of trapezium OABD =1/2×(sum of parallel sides)×height =1/2×(u+v)×t =2(u+v)t =2(u+at)t =u+21at2
