Consider three different raster systems with resolutions of 640 by 480, 1280 by 1024, and 2560 by 2048. What size frame buffer (in bytes) is needed for each of these systems to store 12 bits per pixel? How much storage is required for each system if 24 bits per pixel are to be stored?
Frame-buffer size for each of the systems is 640 × 480 × 12 bits ÷ 8 bits per byte = 450 KB. 1280 × 1024 × 12 bits ÷ 8 bits per byte = 1920 KB. 2560 × 2048 × 12 bits ÷ 8 bits per byte = 7680 KB. For 24 bits of storage per pixel, each of the above values is doubled. 900 KB & 3840 KB & 15360 KB.
