Q9: 1 mole of K4[Fe(CN)6] contains carbon = 6g atoms. 0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms. The mass of carbon present in 0.5 mole of K4[Fe(CN)6] is: (a) 36 g (b) 18 g (c) 3.6 g (d) 1.8 g
Answer: (a) 36g Explanation: 1 mole of K4[Fe(CN)6] contain carbon = 6g atoms 0.5 mole of K4[Fe(CN)6] contain carbon = 3g atoms Mass of carbon in grams = (12g) × [(3g atoms )/(1g atom )] = (12g) × [(3g)/(1g)] = 36g
