17. The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is A.2.05 gram B.3.05 gram C.4.05 gram D.5.05 gram
Answer: Option B Solution: Balanced chemical equation: P4 + 5O2 --------> P4O10 1 mol 5 mol 1 mol 124g 160g 284g Here limiting reagent is P4. So, 124g of P4 produce P4O10 = 284g Therefore, 1.33g of P4 produce P4O10 = (284/124)*1.33 = 3.05g
