The escape velocity from the Earth’s surface is v. The escape velocity from the surface of another planet having a radius, four times that of Earth and same mass density is : (1) 4 v (2) v (3) 2 v (4) 3 v
The correct option is A 4v Escape velocity from the Earth's surface, Ve= √2GM/R =√2G[ρ×(4πR3/3)]R ⇒ve=√8GρπR23 ve∝R (For same density) v1/v2=R1/R2⇒v/v2=R/4R ∴v2=4v
