A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is : (1) 0.628 s (2) 0.0628 s (3) 6.28 s (4) 3.14 s
For a spring, kx=F Given, x=5 cm, F=10 N ⇒k(5×10−2)=10 ⇒k=1000/5=200 N/m Now, for spring-mass system undergoing SHM, T=2π√m/k given, m=2kg ⇒T=2π√2/200=2π/10=0.628 s
