52. The ionisation energy of hydrogen atom in the ground state is x KJ. The energy required for an electron to jump from 2nd orbit to 3rd orbit is A.5x/36 B.5x C.7.2 x D.x/6
Answer: Option A Solution: The ionisation energy for the hydrogen atom can be written as: Ionisation energy = energy in first orbit - energy in infinite orbit Ionisation energy = E = -E0 / n2 , where E0 = 13.6 eV (1 eV = 1.602×10-19 Joules) and n = 1,2,3… and so on. The difference in energy = Einfinity - E1 so the ionisation energy from the ground state = x KJ = 0-( -E0 /12 ) = E0
