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Gagan Mishra

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2 years ago
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47. A body of 4.0 kg is lying at rest. Under the action of a constant force, it gains a speed of 5 m/s. The work done by the force will be ________ A.50 J B.30 J C.20 J D.40 J

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Abhishek Mishra

2 years ago

Option A Solution: Work done = 1/2*m*V2 =1/2*4*52 = 1/2*4*25 = 2*25 = 50 J

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