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Deepika Deepika

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2 years ago
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If a force of 50 N stretches a spring 0.10 m, what is the spring constant?

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Abhishek Mishra

2 years ago

We use Hooke's Law, which states that, F=kx F is the force in newtons k is the spring constant x is the extension of the spring in meters Solving for k, we get, k = F x Now, we plug in the values, and we get, k = 50 N 0.1 m 500N/m

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