Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride
Let the mass of solution be 100g Mass of benzene = 30 g Mass of carbon tetrachloride = 100g- 30g= 70g Number of moles of benzene = Mass/ Molar mass = 30g/ 78gmol-1 = 0.385 mol Number of moles of carbon tetrachloride = Mass/ Molar mass= 70/ 154 gmol-1 = 0.455 mol Mol fraction of benzene = Moles of benzene / Moles of benzene + Moles of carbon tetrachloride 0.385 mol/0.840 mol= 0.458 Ans
