If Kb of HCN is 4.0 × 10-10, then the pH of 2.5 × 10-1 10. molar aqueous HCN is A. 2.0 B. 4.7 C. 5.0 D.2 x 10-5

user image

Muskan Anand

2 years ago

[H+] in a solution of weak acid of conc. C and dissociation constant Kc is given as [H+] = √ Ka × C = √ 4× 10^-10 × 2.5 × 10-1 = √ 1× 10^-10 = 1× 10^-5 pH = -log [H+] = - log 10^-5 = 5

Recent Doubts

Close [x]