When a long spring is stretched by 2cm, its potential energy is U.If the spring is stretched by 10 cm, the potential energy stored in it will be (a) U/5 (b) 5U (c) 10U (d) 25U

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Muskan Anand

2 years ago

U= -kx2 where k= spring constant U1/U2 = x1^2/ x2^2 = 4/ 100 U2=25 U1 or U2 = 25U. So, the correct option D.

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