Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

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Muskan Anand

2 years ago

Charge = 96000 coulomb            Time = 1 hour = 3600 seconds            Potential difference = 50 V            I = Q/T            I = 96000/3600 = 80/3 amp            V = I × R            50 = 80/3 × R            Thus. R = 15/8 ohm            Heat = I2RT            = (80/3)2 × 15/8 × 3600            = 800 × 6000            = 4800000 joules.

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