Percentage Of C, H & N Are Given As Follows : C = 40% H = 13.33% N = 46.67% The Empirical Formula Will Be : (1) Ch2n (2) C2h4n (3) Ch4n (4) Ch3n Doubt Answers

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2 years ago

Percentage of C, H & N are given as follows : C = 40% H = 13.33% N = 46.67% The empirical formula will be : (1) CH2N (2) C2H4N (3) CH4N (4) CH3N

1 Answer

2 years ago

Option 3 For one molecule, C has 1 atom H has 4 atoms N has 1 atom. So, the Empirical formula is CH4N .

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