A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50 km/h. Find (i) displacement of the car. (ii) distance travelled by the car. (iii) average speed of the car.
Speed from A to B = 30 km/h Speed from B to A = 50 km/h Let the distance between the A and B be X. Step 2: Formula used Averagespeed=TotaldistancetraveledTotaltimetaken speed=distancetimetaken Part (a) Step 3: Finding the displacement Since the car travels back to the same position A, its displacement is zero. Displacement is defined as the shortest distance between the initial and final position. In this case, the initial position and final position of the car is the same so displacement is zero. Part (b) Step 4: Finding the average speed Time taken by the car to travel from the A to B = X30 h Time taken by the car to travel from B to A = X50 h . We know, Averagespeed=TotaldistancetraveledTotaltimetaken Putting all the values Averagespeed=2X(X30+X50) After solving Average speed = 37.5 km/h Part (c) Step 5: Finding the total distance Total distance traveled by car = 2×37.5=75m Hence, the total distance covered by car is 75m.
