A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming the acceleration is uniform, find (i) the acceleration. (ii) the distance travelled by the train for attaining this velocity.
v=72 km/h (final velocity) =72×185=20 m/s u=0 (initial velocity) t=5 min (time) =5×60=300sec Step 2 - Find acceleration v=u+at 20=0+a(300) a=151m/s2 (acceleration) Step 3 - Distance travelled by train By second equation of motion S=ut+21at2 S=0+21(151)(300)2 S=3000 m (distance)
