The distance between two bodies becomes 6 times more than the usual distance. The the F becomes a. 36 times b. 6 times c. 12 times d. 1/36 times
Option d. Simply, new force will be reciprocal of square of given new distance. In the above question the distance becomes 6 times therefore, taking square of 6 and reciprocal it which is 1/36. Hence the new force will become 1/36 times the previous force.
