Using a horizontal force of 200 N, we intend to move a wooden cabinet across a floor at a constant velocity. What is the friction force that will be exerted on the cabinet?
Step 1 of 3 As the velocity of the cabinet is constant, its acceleration must be Zero i.e., a = 0 Step 2 of 3 Then using 2nd law of motion, force will be zero as acceleration is zero. F = ma F = 0 Therefore, no force is spent in accelerating the cabinet. Step 3 of 3 Now, the magnitude of the force acting in opposite direction i.e. Frictional force is equal to the force exerted on the wooden cabinet which is 200 N. Hence, the total Frictional Force of 200 N is exerted on the cabinet. F = f = 200 N Final answer Frictional force exerted on the cabinet is 200 N.
