y=log sinx तो d/dx (dy/dx) को हल करे
Let sinx = u Therefore by applying chain rule, dy/dx = d log u / du * d sin x / dx dy / dx = 1/u * cos x = 1/sin x * cos x = cot x. Hence dy/dx = cot x when y = log ( sin x )
i think its correct
you can check
thank you for the question
dy/dx=sec२x
