Q.1. 183, 206, 160, 229, (?), 252, 114
(1) 137
(2) 183
(3) 137
(4) 229
(5) 206
Answer: 1
Solution:
The logic follows here is-
183 + 23 = 206
206 - 46 = 160
160 + 69 = 229
229 - 92 = 137
137 +115 = 252
252 - 138 = 114
Q.2. 188, (?), 140, 132, 128, 126, 125
(1) 125
(2) 154
(3) 132
(4) 126
(5) 154
Answer: 5
Solution:
The logic follows here is-
186 – 32 = 154
154 - 16 = 140
140 - 8 = 132
132 - 4 = 128
128 - 2 = 126
126 - 1 = 125
Q.3. 9, 15, 49, (?), 961, 5759
(1) 5759
(2) 961
(3) 191
(4) 49
(5) 15
Answer: 3
Solution:
The logic follows here is-
(9 × 2) – 3 = 15
(15 × 3) + 4 = 49
(49 × 4) – 5 = 191
(191 × 5) + 6 = 961
(961 × 6) - 7 = 5759
Q.4. 2442, 1222, 614, 312, 163, (?), 55.75
(1) 1222
(2) 312
(3) 89.5
(4) 614
(5) 163
Answer: 3
Solution:
The logic follows here is-
2442/2 + 1 = 1222
1222/2 + 3= 614
614/2 + 5 = 312
312/2 + 7 =163
163/2 + 9 = 89.5
89.5/2 + 11 = 55.75
Q.5. 10, 12, 27, 85, (?), 1731, 10393
(1) 116
(2) 463
(3) 771
(4) 345
(5) 234
Answer: 4
Solution:
The logic follows here is-
10 x 1 + 2 = 12
12 x 2 + 3 = 27
27 x 3 + 4 = 85
85 x 4 + 5 = 345
345 x 5 + 6 = 1731
1731 x 6 + 7 = 10393
Directions (Q.6 –10): -Read the following information carefully to answer the questions.
In annual seminar of three companies, A, B and C. some male and female employees represent their companies. Average number of female employees who represent A and B is 420. Total male employee in A and B is 1620. Number of female employees is 2/3rd and 2/5th of male employee in A and B respectively.
Source: safalta.com
Total female employee who represent C are 25% more than total female employee who represent A. Total male employee who represent C are 33 1/3% more than total female employee who represent B.Q.6:-Total employees who represent A is what percent more than total male employee who represents B?
(1) 331/3 %
(2) 301/3 %
(3) 271/3 %
(4) 391/3 %
(5) None of these
Answer: 1
Solution:
Required % = (1200-900)/900 ×100= 33 1/3%
By passage
Female in A+ Female in B = 840
Male in A + Male in B = 1620……. (1)
According to passage
2/3 Male in A= Female in A and 2/5 Male in B = Female in B
So, 2/3 Male in A + 2/5 Male in B = 840……… (2)
On solving eq. 1 and 2 we get
Male in A = 720, Male in B = 900, Female in A = 480 and Female in B = 360
Male Female Total
A 720 480 1200
B 900 360 1260
C 480 600 1080
Total 2100 1440 3540
Q.7. 25% of total female employee and 20% of total male employee together have MBA degree, then find total employee who do not have MBA degree?
(1) 2880
(2) 2760
(3) 2450
(4) 2780
(5) None of these
Answer: 2
Solution:
Employee who do not have MBA= 75% of 1440 + 80% of 2100
= 1080+1680 = 2760
Q.8.Find the ratio between total male employee who represent B & C together to total female employee who represent A & C together?
(1) 23:13
(2) 23:14
(3) 23:18
(4) 23:12
(5) None of these
Answer: 3
Solution:
Required ratio = (900+480): (480+600)
= 1380: 1080
= 23: 18
Q.9. Find difference between Total male employees who represent C and total female employee who represent B?
(1) 120
(2) 140
(3) 100
(4) 160
(5) None of these
Answer: 1
Solution:
Required Difference = 480-360 = 120
Q.10. Find average number female in B & C?
(1) 480
(2) 420
(3) 520
(4) 540
(5) None of these
Answer: 1
Solution:
Average = (360 + 600)/2 = 480
