# Quantitative Aptitude Quiz for SSC (Simplification): 16 March 2021

Updated Tue, 16 Mar 2021 09:39 PM IST

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1. What is 333 times 135?

a) 44655
b) 44755
c) 44855
d) 44955

333 times 135 = 333 × 135 = 44955

2. What will come in place of the question mark in the following equation?

(49/10) + (3/11) + (7/15) = ?

a) 5 (213/330)
b) 5 (211/330)
c) 5 (215/330)
d) 5 (217/330)

(49/10) + (3/11) + (7/15) = ?

⇒ [(49 × 33) + (3 × 30) + (7 × 22)]/330

⇒ (1617 + 90 + 154)/330

⇒ 1861/330

⇒ 5 (211/330)

3. What should come in place of the question mark (?) in the following question?

1/4th of 1/2 of 3/4th of 52000 = ?

a) 4475
b) 4575
c) 4775
d) 4875

1/4th of 1/2 of 3/4th of 52000

⇒ (1/4) × (1/2) × (3/4) × 52000

⇒ (52000 × 3)/32

⇒ 1625 × 3

⇒ 4875

4. What will come in place of question mark in the following equation?

283 × 56 + 252 = 20 × ?

a) 905
b) 605
c) 805
d) 705

283 × 56 + 252 = 20 × x

⇒ 15848 + 252 = 20 × x

⇒ 16,100 = 20 × x

⇒ x = 805

5. What will come in place of question mark (?) in the following question?

(5863 - √2704) × 0.5 = ?

a) 2705.5
b) 2605.5
c) 2905.5
d) 2805.5

(5863 - √2704) × 0.5 = x

⇒ (5863 – 52) × 0.5 = x

⇒ x = 2905.5

6. What will come in place of question mark (?) in the following question?

76% of 1285 = 35% of 1256 + ?

a) 527
b) 537
c) 547
d) 557

76% of 1285 = 35% of 1256 +?

⇒ (76/100) × 1285 = (35/100) × 1256 +?

⇒ 97660/100 = 43960/100 +?

⇒ ? = (97660/100) – (43960/100)

⇒ ? = 53700/100 = 537

7.  In the following question, two equations numbered I and II are given. You have to solve both the equations and give answer

I. √500 x + √402 = 0

II.

Source: safalta

√360 y + √200 = 0

a) x < y
b) x > y
c) x = y
d) none of the above

x = -√402/√500 = -√(402 × 18)/√(500 × 18) = -√7236/√9000

y = -√200/√360 = -√(200 × 25)/√(360 × 25) = -√5000/√9000

Now, as -√7236 < -√5000

Hence, x < y.

8. The sum of 15% of a positive number and 20% of the same number is 126.What is one-third of that number?

a) 100
b) 120
c) 140
d) 160

Let the number = x

According to the question

⇒ (15/100) × x + (20/100) × x = 126

⇒ (35/100) × x = 126

⇒ x = 12600/35 = 360

We want to find out x/3

∴ x/3 = 360/3 = 120

9. If 70% of a number is subtracted from itself it reduces to 81.what is two fifth of that no.?

a) 108
b) 118
c) 98
d) 128

Let the number be m.

Then m – 70 % of m = 81

⇒ m – 70/100 × m = 81

⇒ m – 0.7m = 81

⇒ 0.3m = 81

⇒ m = 81/0.3

⇒ m = 270

According to question:

Now, we need to find 2m/5

= 2 × 270 / 5

= 2 × 54

= 108

10. What will come in the place of the question mark '?' in the following question?

986 × 237 + 986 × 863 = ?

a) 1064600
b) 1074600
c) 1094600
d) 1084600

We are given 986 x 237 + 986 x 863

Hence taking 986 common

We have 986 × (237 + 863)

? = 986 × 1100

? = 1084600

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