# Quantitative Aptitude Quiz for UPSI : 05 May 2021 Source: SAFALTA
1) Today it is Thursday.After 132 days,it will be

A Monday
B Sunday
C Wednesday
D Thursday

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2) A train 120 meters long is running with a speed of 60 km/hr. In what time will it pass a boy who is running at 6 km/hr in the direction opposite to that in which the train is going?

A 6.54 sec
B 44.32 sec
C 55 sec
D  30.2 sec

3) Devesh can cover a certain distance in 1 hour 24 minutes by covering two-third of the distance at 6 km/hour and the rest at 7 km/hr. Calculate total distance.

A 8 km
B 9 km
C 6 km
D 7/5 km

4) Find the H.C.F, if the numbers are in the ratio of 4 : 5 : 6 and their L.C.M. is 2400.

A 35
B 20
C 40
D 67

5) What is the value of c , If 8 is 4% of a, and 4 is 8% of b. c equals b/a.

A 12
B 1/4
C 0.155
D None of these

6) P and Q take part in 100 m race. P runs at 6kmph. P gives Q a start of 8 m and still beats him by 8 seconds. The speed of Q is:

A 6.14 kmph
B 15.2 kmph
C 5 kmph
D 4.86 kmph

7) Find the speed of the boat in still water, if a boat covers a certain distance upstream in 2 hours, while it comes back in 1`1/2` hours. If the speed of the stream be 3 kmph.

A 12 Kmph
B 18 Kmph
C 21 Kmph
D 24 Kmph

8) In covering a distance of 40 km, Kamlesh takes 2 hours more than Pankaj. If Kamlesh doubles his speed, then he would take 1 hour less than Pankaj. Then what is Kamlesh's speed?

A 11 Kmph
B 5 Kmph
C 9 Kmph
D 6 Kmph

9)  Find the speed of the train, if a train 142 m long passes a pole in 6 seconds.

A 77.2 km/hr
B 79.6 km/hr
C 84.9 km/hr
D 79.2 km/hr

10) The rate at which a sum becomes four times of itself in 25 years at S.I.,will be:

A 30%
B 25%
C 12%
D 49%

Solution:

1.
Explanation:
Since each day of the week is repeated after 7 days.
After 133 days,it will be thursday. So one day before that would be Wednesday.
2.
Speed of train relative to boy= `(60 + 6)` km/hr = 66 km/hr
`= [66 xx 5/18]` m/sec = `[55/3]` m/sec.
Time taken to pass the boy=` [120 xx 3/55]` sec = 6.54 seconds

3.
Let the total distance be x , then
`[{(2/3) x }/6 ] + [{(1/3) x }/7 ] = 7/5`
`=> x/9 + x/21 = 7/5`
`=> 7x = 63`
`=> x = 9`

Therefore , total distance = `6 km`

4.
Let the numbers be 3x, 4and 5x.
Then,their L.C.M. = 120x.
So, 120= 2400 or x = 20.
=>The numbers are (4 x 20), (5 x 20) and (6 x 20).
Hence, required H.C.F = 20.

5.
Let be the 4% of a is 4a/100.
Since this equals 8, we have 4a/100=8.
Solving for a yields a=8×`(100/4)`=200.
Also, 8% of b equals 8b/100, and this equals 4.
Hence, we have `(8/100)`×b=4.
Solving for b yields  b = 50.
Now, c=`b/a`=`50/200`=`1/4.`

6.
`speed =( 6**5/18)m/sec) = (30/18) m/sec`
Time taken by P to cover 100 m = `(100 ** 18/30)`m/sec =60 sec
Time taken by Q to cover 92 m = (60 + 8) = 68 sec.
Q's speed =`("Distance"/"Time"**18/5) kmph =(92/68 ** 18/5)` kmph = 4.86kmph.

7.
Let the speed of the boat in still water be kmph. Then,
Speed downstream = (+ 3) kmph,
Speed upstream = (- 3)kmph.
`(x - 3) * 2 = (x + 3) * 3/2`
4x - 12 = 3x + 9
= 21kmph.

8.
Let Kamlesh’s speed be x km/hr.
Then, `40/x - 40/(2x) = 4`
8x = 40
x = 5 km/hr

9.
Speed = `[142/6]` m/sec
= `[23.6 ** 18/5]` km/hr
= 84.9 km/hr

10.
Let sum = x. Then, S.I. = 3x
Rate = `[100 ** (S.I.) / P**T] %`
= `[100 ** (3x) / x ** 25]% = 12%`

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