Quantitative Aptitude Quiz for UPSI : 22 April 2021

Q 1 - A vendor bought 6 oranges for Re 10 and sold them at 4 for Re 6. Find his loss or gain percent.
A - 8% gain
B - 10% gain
C - 8% loss
D - 10% loss
Q 2 - By selling 33 meters of cloth, one gains the selling price of 11 meters. Find the gain percent.
A - 50%
B - 45%
C - 40%
D - 60%
Q 3 - Pure ghee costs Re 100 per kg. A shopkeeper mixes vegetable oil costing Re 50 per kg and sells the mixture at Re 96 per kg, making a profit of 20%. In what ratio does he mix the pure ghee with the vegetable oil.
A - 3:2
B - 2:3
C - 4:3
D - 3:1
Q 4 - The CP of 25 articles is equal to SP of 20 articles. Find the loss or gain percent.
A - 35%
B - 30%
C - 25%
D - None of these
Q 5 - A shopkeeper bought 80 kg of sugar at Re 13.50/kg and mixed it with 120 kg sugar at Re 16/kg. If he is to make a profit of 16% what rate should he sell the sugar to his customers?
A - Re 12/kg
B - Re 15.25/kg
C - Re 17/kg
D - Re 17.40/kg
Q 6 - A man bought cookies at 3 for a rupee. How many for a rupee should he sell to make a profit a 50%.
A - 1
B - 2
C - 1.5
D - None of these
Q 7 - Anil buys a calculator for Re 600 and sells it to Vikash at 10% profit. Vikash sells it to Chandan for 5 % profit. Chandan after using it for certain time, sells it to Dinesh at a loss of 20%. For how much Chandan sell the calculator to Dinesh.
A - Re 550.50
B - Re 564.40
C - Re 554.40
D - None of these
Q 8 - An article is sold by X to Y at a loss of 20%, Y to Z at a gain of 15%, Z to W at a loss of 5% and W to V at a profit of 10%. If v had to pay Re 500, how much X paid for it?
A - Re 520.07
B - Re 490.07
C - Re 510.07
D - Re 530.07
Q 9 - A vendor when could not find buyers for his vegetable at Re 10/kg, reduced the rate to Re 8.10 per kg but uses a faulty weight of 900 gm in place of 1 kg weight. Find the percent change in the actual price or loss.
A - 8%
B - 8.10%
C - 9%
D - 10%
Q 10 - A trader marks the SP of an object at a profit of 20%. Considering the demand o the object, he further increases the price by 10%. Find the final profit %.
A - 35%
B - 31%
C - 32%
D - 25%
 
 
 
 
Solution:
1.
Answer - D
Explanation
Suppose, number of oranges bought = LCM of 6 and 4 = 12
∴CP = Re (10/6 * 12) = Re 20 and SP = Re (6/4 * 12) = Re 18
∴Loss% = (2/20 * 100)% = 10%
 
2.
 
Answer - A
Explanation
(SP of 33m) - (CP of 33m) = Gain = SP of 11m
∴ SP of 22m = CP of 33m
Let CP of each meter be Re 1. Then, CP of 22m = Re 22.
Hence SP of 22m = Re 33.
∴ %Gain = 11/22 * 100
= 50%
 
3.
Answer - A
Explanation
Mean Cost price = Re (100/120)*96 = Re 80 per kg
Apply rule of allegation,
there4; Required ratio = 30:20 = 3:2
 
4.
Answer - C
Explanation
Let the CP of each article = Re 1.
Then CP of 20 articles = Re 20.
SP of 20 articles = CP of 25 articles = Re 25.
∴ Gain% = (5/20)*100% = 25%
 
5.
Answer - D
Explanation
CP of 200 kg of mixture = Re (80 * 13.50) + (120 * 16) = Re 3000
SP = 116% of Re 3000 = Re (116/100)*3000 = Re 3480
∴Rate of SP = Re 3480/200 = Re 17.40/kg
 
6.
Answer - B
Explanation
CP of 3 cookies = Re 1
SP of 3 cookies = 150% of Re 1 = 3/2
 
For Re 3/2, the man sells 3 cookies.
Hence for Re 1, number of cookies sold = 3*2/3 = 2
 
7.
Answer - C
Explanation
SP for Chandan = 600 * (110/100) * (105/100) * (80/100)
= 600 * 924/1000
= Re 554.40
 
8.
Answer - A
Explanation
CP for X = 500 * (100/80) * (100/115) * (100/95) * (100/110)
= 500 * 10000/9614
= Re 520.07
 
9.
Answer - D
Explanation
After the price was reduced, 900 gm now costs Re 8.10.
Hence 1000gm will cost (1000/900)*8.10 = Re 9
% change in actual price or loss = [(10 - 9)/10]*100%
= 10%
 
10.
Answer - C
Explanation
 
Let the CP = Re 100
∴ SP = 100 * (120/100) * (110/100)
= Re 132
 
Final profit = (132 - 100)*100%
= 32%