An organic compound containing C, H, and O gave the following percentage composition: C = 40.687%. H = 5.085% O = 54.228% The vapor density of the compound is 59. Calculate the molecular formula of the compound.
Consider →100 g of compound MassesMolar massMoles Ratios Ratio C40.3687 12 3.3916 3.4/3.4=1 2 H5.085 1 5.085 5.1/3.4=1.5 3 O54.228 16 3.392 3.4/3.4=1 2 Emperical formula =C2H2O2 Emperical mass =2×12+3×1+2×16 =24+3+32 =59 Molecular mass =2×vapor density =2×59=118 n=E.MM.M=59118=2 Molecular formula =n×E.F=2×C2H3O2 =C4H6O4
