# Quantitative Aptitude Quiz For IBPS PO/Clerk Prelims 2022- 11th August

Safalta Expert Published by: Nikesh Kumar Updated Thu, 11 Aug 2022 06:08 PM IST

1) In the World cup, Virat scored an average of 83 runs per match in the first 3 matches and an average of 86 runs per match in the last four matches. What is ViratтАЩs average run for the first match and the last match if his average run per match for all five matches is 84.8?

Option 1: 75
Option 2: ┬а82
Option 3: ┬а80
Option 4: ┬а84
Option 5: ┬а85

Explanation:
I + II + III = 83 ├Ч 3 = 249┬а тАжтАж (i)
II + III + IV + V = 86 ├Ч 4 = 344 тАжтАж (ii)
I + II + III + IV + V = 84.8 ├Ч 5 = 424 тАж.. (iii)
From equation (ii) and (iii)
I = 80 тАжтАж┬а (iv)
Now, From Equation (i), (ii) and (iv)
IV + V = 175┬а┬а тАжтАж (v)
From equation (i), (iii) and (v)
I + V = 164
Therefore required average=┬а164/2=82
┬а

2) The average age of 16 students and their teacher's age is 16 years. If the teacher's age is excluded, the average reduces by 2. What is the teacher's age?┬а

Option 1: ┬а36
Option 2: ┬а30
Option 3: ┬а38
Option 4: ┬а48
Option 5: ┬а32

Explanation:
16S + T = 16 ├Ч 17
┬а16S + T = 272 years
After excluding the age of teacher average of 16 students are,
16S = 14 ├Ч 16
= > 224 years
Therefore teacherтАЩs age = 272 тАУ 224 = 48 years

3)┬аThe sum of five consecutive even numbers is 128 more than the average of these numbers.

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What is the third of these numbers?
┬а

Option 1: ┬а36
Option 2: ┬а30
Option 3: ┬а28
Option 4: ┬а42
Option 5: ┬а32

Explanation:
Let the five consecutive even numbers be x, x+2, x+4, x+6 and x+8.
ATQ,
(x+x+2+x+4+x+6+x+8) тАУ {( x+x+2+x+4+x+6+x+8)/5} = 128
25x + 100 тАУ 5x тАУ 20 = 640
20x = 640 тАУ 80
20x = 560
X = 28
Therefore, the required third number = 32.

General English Quiz┬а-┬а10th August
Reasoning Quiz-┬а10th August

4)┬аRatio of sum of 2/5 of the present age of Anu and present age of Nila to the present age of Nila is 2:1. If the average present age of Anu, Nila and Mala is 27 years and the age of Mala after 15 years is 60% more than her present age, find the present age of Nila?┬а

Option 1: ┬а16
Option 2: ┬а20
Option 3: ┬а24
Option 4: ┬а12
Option 5: ┬а8

Explanation:
M + 15 = 160/100 * M 5M + 75 = 8M
M = 25
A + N = 27 * 3 тАУ 25 = 56 (2/5 A + N)/N = 2/1
2/5 * A =┬аN┬аA/N = 5/2
N + 5N/2 =┬а56┬а7N/2 = 56
N = 2/7 * 56 = 16

5)┬аThe sum of three consecutive odd numbers is 657. Also average of four consecutive even numbers is 84. What is the sum of smallest odd number and second largest even number?┬а

Option 1: ┬а222
Option 2: ┬а202
Option 3: ┬а.239
Option 4: ┬а269
Option 5: ┬а214

Explanation:
Let odd numbers is=x+2,x,x-2.
So, 3x=657
So, x=657/3=219
Now even number is y,y+2,y+4,y+6 So, 4y=84-12=72
So, y=18
Second largest even is 22
Smallest odd=217
Required sum is=239

6)┬аAverage weight of three friends A, B and C is 53 kg. Another person D joins the group and now the average is 49 kg. If another person E whose weight is 8 kg more than D, joins the group replacing A, then average weight of B, C, D and E becomes 51 kg. What is the weight of A (in kg)?┬а

Option 1: ┬а40 kg
Option 2: ┬а35 kg
Option 3: ┬а45 kg
Option 4: ┬а37kg
Option 5: ┬а42kg

Explanation:
Average = Total/number of terms
Calculation
A + B + C = 53 ├Ч 3 = 159 kg
A + B + C + D = 49 ├Ч 4 = 196kg┬а┬а┬а┬а┬а ---- (I)
тЗТD = 196 тАУ 159 = 37 kg
So, E = D + 8
E = 37 + 8 = 45 kg
Now,
B + C + D + E = 51 ├Ч 4 = 204 kg┬а┬а┬а┬а┬а ---- (II)
From equation (I) and (II),
E тАУ A = 204 тАУ 196 = 8 kg
тЗТ45 тАУ A = 8
тЗТA = 37 kg
┬а
7)┬аIf the average temperature of first four days of week was 39┬░ C and the average temperature of the week was 40┬║C, then what was the average temperature of the last three days of the week?┬а

Option 1: ┬а63.3
Option 2: ┬а12.3
Option 3: ┬а40.3
Option 4: ┬а41.33
Option 5: ┬а14.3

Explanation:
Total temperature of first four days=39*4=156
Total temperature of the week is=40*7=280
Total temperature of last three days=280-156=124
Average temperature of last three days =124/3=41.3

8) The average expenditure of a man for the first six month is Rs.12000 and for the next six months is Rs.10000.If save 14000 in that year the find average monthly income?

Option 1: ┬а1443.6
Option 2: ┬а12166.66
Option 3: ┬а5636.36
Option 4: ┬а147.36
Option 5: ┬а1236.36

Explanation:
Total expenditure in first 6 months is=12000*6=72000
Total expenditure in last 6 month is=10000*6=60000
Total income of the man in a year is =72000+60000+14000=146000
So average income in a month is =146000/12=12166.66

9) The average age of 16 students and their teacher's age is 16 years. If the teacher's age is excluded, the average reduces by 2. What is the teacher's age?┬а

16S + T = 16 ├Ч 17
┬а16S + T = 272 years
After excluding the age of teacher average of 16 students are,
16S = 14 ├Ч 16
= > 224 years
Therefore teacherтАЩs age = 272 тАУ 224 = 48 years

10)┬аIn a class with a certain number of students if a teacher weighing 72 kg is added, then the average weight of the class is increased by 2 kg. If one more teacher weighing 54 kg is added, then the average weight of the class increases by 3 kg over the original average. What is the original average weight (in kg) of the class?┬а

Option 1: ┬а50
Option 2: ┬а30
Option 3: ┬а┬а20
Option 4: ┬а60
Option 5: ┬а40

Explanation:

Let the students in a class be x
And average weight of class is y
ATQ,
(xy+72)/(x+1) = y+2
тЗТ xy + 72 = xy + 2x + y + 2
тЗТ 2x + y = 70 тАжтАж(i)
Now, another teacher joined the class
(xy+72+54)/(x+2) = y+3
тЗТ xy + 126 = xy + 3x + 2y + 6
тЗТ 3x + 2y = 120 тАжтАж.(ii)
By equation (i) and (ii),
Number of students
X = 20
тИ┤ Original average weight,
Y = 30 kg
┬а